结合两个 SQL 查询及其结果

Question

I am using Oracle database and I have written one SQL query using joins as below:

SELECT
(CT.CRDATTIM || CT.RECORDCD || CT.CRNODE) AS CALLERKEY 
FROM
   W67U999S F 
   JOIN
      W03U999S CT 
      ON F.CCRDATTIM = CT.CRDATTIM 
      AND F.CRECORDCD = CT.RECORDCD 
      AND F.CCRNODE = CT.CRNODE 
      AND F.CRECORDCD = 'T' 
      AND CT.WRKTYPE = 'CALLER' 
   JOIN
      PQCUSTSRV CDT 
      ON F.CCRDATTIM = CDT.CRDATTIM 
      AND F.CRECORDCD = CDT.RECORDCD 
      AND F.CCRNODE = CDT.CRNODE 
WHERE
   F.PCRDATTIM = '2019-01-29-06.10.33.037940' 
   AND F.PRECORDCD = 'F' 
   AND F.PCRNODE = '01' 
   AND CT.CRDATTIM < '9999-12-31-23.59.59.999999'

The above query returns me the following rows of data:

CALLERKEY
----------
2019-01-29-06.10.33.310940T01
2019-03-26-00.51.05.124040T01
2019-03-26-00.51.07.993040T01
2019-03-26-00.51.35.531040T01
2019-04-02-04.02.42.280040T01

Now I want to query for each row using the following SQL query to get some additional data that I am interested in: Example as below:

SELECT COUNT(*) AS TESTCOUNT FROM PQCUSTSRV where CALLERKEY='2019-01-29-06.10.33.310940T01' AND TO_TIMESTAMP(CRDATTIM,'YYYY-MM-DD HH24.MI.SS.FF') 
      BETWEEN ADD_MONTHS(SYSTIMESTAMP,-12) AND SYSTIMESTAMP  
  

The above query returns the following data:

TESTCOUNT
------------
2

Now I want to combine the above two queries and get the output as something like below:

CALLERKEY                           TESTCOUNT                                               
----------                          --------    
2019-01-29-06.10.33.310940T01       2
2019-03-26-00.51.05.124040T01       3       
2019-03-26-00.51.07.993040T01       2
2019-03-26-00.51.35.531040T01       1
2019-04-02-04.02.42.280040T01       4

How can I achieve that? Please let me know if you need any additional information.

Answer 1

with t as (
      <first query here>
     )
select t.callerkey, count(p.callerkey) AS TESTCOUNT
from t left join
     PQCUSTSRV p
     on p.callerkey = t.callerkey and
        to_timestamp(p.CRDATTIM, 'YYYY-MM-DD HH24.MI.SS.FF') >= add_months(SYSTIMESTAMP, -12) 
group by t.callerkey;

I changed the logic of the date comparison to just use >= , assuming that you don't have future values in crdattim .

Answer 2

You can use group by as follows:

Select F.CALLERKEY, COUNT(1) AS CNT
  From (your_first_query) f
  Left Join PQCUSTSRV s
    On s.CALLERKEY=f.CALLERKEY AND TO_TIMESTAMP(CRDATTIM,'YYYY-MM-DD HH24.MI.SS.FF') 
      BETWEEN ADD_MONTHS(SYSTIMESTAMP,-12) AND SYSTIMESTAMP  
 Group by f.callerkey

Answer 3

Not tested but this should work

SELECT A.CALLERKEY, COUNT(*) AS TESTCOUNT 
(SELECT (CT.CRDATTIM || CT.RECORDCD || CT.CRNODE) AS CALLERKEY
   FROM W67U999S F
        JOIN W03U999S CT
           ON     F.CCRDATTIM = CT.CRDATTIM
              AND F.CRECORDCD = CT.RECORDCD
              AND F.CCRNODE = CT.CRNODE
              AND F.CRECORDCD = 'T'
              AND CT.WRKTYPE = 'CALLER'
        JOIN PQCUSTSRV CDT
           ON     F.CCRDATTIM = CDT.CRDATTIM
              AND F.CRECORDCD = CDT.RECORDCD
              AND F.CCRNODE = CDT.CRNODE
  WHERE     F.PCRDATTIM = '2019-01-29-06.10.33.037940'
        AND F.PRECORDCD = 'F'
        AND F.PCRNODE = '01'
        AND CT.CRDATTIM < '9999-12-31-23.59.59.999999')A, PQCUSTSRV B
 WHERE A.CALLERKEY=B.CALLERKEY AND TO_TIMESTAMP(CRDATTIM,'YYYY-MM-DD HH24.MI.SS.FF')
      BETWEEN ADD_MONTHS(SYSTIMESTAMP,-12) AND SYSTIMESTAMP
 GROUP BY B.CALLERKEY