我想打开一个文件对话框并将所选文件的位置作为参数传递给 tkinter 以在 gui 上显示？

Question

I am facing the problem that the filedialogue is returning _io.TextIOWrapper object while tkinter takes location of the file as string.

I tried every method to convert this _io.TextIOWrapper to string but failed.

Help me out!!

import tkinter as tk
import tkinter.filedialog

from PIL import Image, ImageTk


class App(tk.Tk):
    def __init__(self):
      super().__init__()

      self.main = tk.Frame(self)
      self.main.grid(row=0, column=0)

      dial = tkinter.filedialog.askopenfile()

      self.disp_img = Image.open(dial).resize((400, 400))
      self.disp_img = ImageTk.PhotoImage(self.disp_img)

      self.img_label = tk.Label(self.main, image=self.disp_img)
      self.img_label.grid(row=0, column=0)


if __name__ == '__main__':
   app = App()
   app.withdraw()
   app.mainloop()

Answer 1

As said in a comment on the question, you want to use askopenfilename() instead of askopenfile() . Alternatively, the TextIOWrapper object has a variable called name which contains the file name.