如何在 python 中生成新的未来每小时时间戳？

Question

I am writing this code to create a current timestamp:

datetime.datetime.fromtimestamp(time.time()).strftime('%Y-%m-%d %H:%M:%S')

This gives the following output:

'2020-07-02 01:00:00'

I want to generate all 24 hours of timestamp for a particular day, something like:

'2020-07-02 00:00:00'
'2020-07-02 01:00:00'
'2020-07-02 02:00:00'
'2020-07-02 03:00:00'
'2020-07-02 04:00:00'
'2020-07-02 05:00:00'
'2020-07-02 06:00:00'
.
.
.
'2020-07-02 22:00:00'
'2020-07-02 23:00:00'

One idea I have in mind, is to copy the date 24 times and create a string like 00:00:00 and then use some logic to increment it by one until 23:00:00 and then concatenate dates and these strings and then convert it into datetime object.

However, this seems like a lot of work if I want to do if its for 10 days that is 240 hours and 10 different dates in future.

Is there a logic that you can suggest to achieve future timestamps for all 24 hours (no minutes, no seconds) for however many days I require?

Something like:

number_of days = input('How many days timestamps do you need?')

my_timestamp_function(number_of_days):

   some_logic_using_the_number_of_days

   return pd.Series(output)

Thank you, Viphawee

Answer 1

you can use datetime.timedelta(hours=1)

def generate_datetimes(date_from_str='2020-01-01', days=3):
   date_from = datetime.datetime.strptime(date_from_str, '%Y-%m-%d')
   for hour in range(24*days):
       yield date_from + datetime.timedelta(hours=hour)

for date in generate_datetime():
    print(date.strftime('%Y-%m-%d %H:%M:%S'))

and you will get

2020-01-01 00:00:00
2020-01-01 01:00:00
2020-01-01 02:00:00
...
2020-01-03 22:00:00
2020-01-03 23:00:00