如何搜索字符串的所有出现的 substring 并将该 substring 旁边的 valuenext 存储到 python 中的变量中？

Question

string s1 = "abc:12 Hellow world abc:342 hi there abc:15 Here,in python,I want to search all 'abc' and store the value after semicolon. To be more specific,if I search 'abc' substring,then 12;342;15 value would be stored in variable.

Answer 1

this regex finds all abc<optional whitespaces>:<optional whitespace><value> where <value> must not contain whitespace characters or quotes...

import re
data = """
string s1 = "abc:12 Hellow world abc :342 hi there abc :15"
"""

l = re.findall(r'abc\s*:\s*([^\s\"\']+)', data)
print(l)

l is your list of values and holds ['12', '342', '15']

according to your specification, this is not restricted to numerical values (you might want to adapt the regex if your values can only be integer numbers)

Answer 2

You can use regular expressions:

import re

string = "abc:12 Hellow world abc :342 hi there abc :15"
pattern = re.compile(r"abc.*?:(.+?)\b")
matches = pattern.findall(string)

print(matches) # ['12', '342', '15']

Demo: https://regex101.com/r/gAQwVs/1

Answer 3

Try this

Based on you'r input!

 a = [int(x.split(" ")[0][1:]) for x in s1.split("abc")[1:]]
 print(a)

Output

 [12, 342, 15]