如何过滤查询 Sql 以便在同一表的多个行具有两个相同值时仅显示一个值？

Question

Example: I have a table "person" with 6 columns: id, name, lastname, age, job, genre. I need to make a query SELECT so that it shows only one value when a person has both the same age and job.

Person:

+--------+------------+--------+--------+---------+
| id     | name       |lastname| age    | job     |
+--------+------------+--------+--------+---------+
|    101 | francesco  | pieri  | 18     | soldier | 
|    102 | martin     | gofman | 25     | grocer  | 
|    103 | paulina    | arani  | 44     | engineer| 
|    104 | george     | gobelt | 25     | grocer  |
|    105 | marcus     | derona | 18     | soldier |
+--------+------------+--------+--------+---------+

I want the result to show up something like this

+--------+------------+--------+--------+---------+
| id     | name       |lastname| age    | job     |
+--------+------------+--------+--------+---------+
|    101 | francesco  | pieri  | 18     | soldier | 
|    102 | martin     | gofman | 25     | grocer  | 
|    103 | paulina    | arani  | 44     | engineer| 
+--------+------------+--------+--------+---------+

I don't care about the order or the way the row are grouped, just need that a row with same age and job is shown ONCE.

I tried something with partition by and row number, but only found examples with conditions on a single field and I don't know how to merge it with my personal case.

Answer 1

You can use row_number() for this:

select t.*
from (select t.*, row_number() over (partition by age, job order by id) as seqnum
      from t
     ) t
where seqnum = 1;