如何将命令的 output 作为对 bash shell 中的变量的引用

Question

I am creating a bash file.sh which will locate the path of a file and store the output of that command to use it later in another command. This is what I've done so far:

path_exe=${1:-locate binarycreator}
$path_exe -c config/config.xml -p packages $Name

when I'm running it I'm getting this: "locate: invalid option -- 'p'" Can anyone help me on this please?

Answer 1

You have to store the first variable as a command. See below example which highlights what you are doing and how it is to be done.

bash-5.0$ a=${1:-'which ls'}
bash-5.0$ echo $a
which ls
bash-5.0$ $a
/usr/bin/ls  # Notice only the command is printed but not executed.

--------------------------------------------- 

bash-5.0$ a=$(which ls)
bash-5.0$ echo $a
/usr/bin/ls
bash-5.0$ $a
aliases        bin 
# This executed the command