将列表转换为字典，列表中的最后一个元素将是值，rest 将是键

Question

I have a list of items, for example:

items = ['BANANA', 'FRIES', 12]

I want items[-1] to be the value of a dict and the rest will be the key like:

dict = {'BANANA FRIES': 12}

I want a piece of code that does it for any list of any length so that the last element is the value and the rest will be the key. Thank you.

Answer 1

{' '.join(items[:-1]): items[-1]} 

Answer 2

Try this one. It will work for any length of list :

items = ['BANANA', 'FRIES', 12]
di = {}
di[' '.join([item for item in items[:-1]])] = items[-1]
print(di)

Answer 3

The shortest way to do this:

my_list = ['BANANA', 'FRIES', 12]
my_dict = { ' '.join(my_list[:-1]) : my_list[-1] }

Doing this task with a function:

def convertToDict(my_list):
    return { ' '.join(my_list[:-1]) : my_list[-1] }

items = ['BANANA', 'FRIES', 12]
items_dict = convertToDict(items)
print(items_dict)

Result: { 'BANANA FRIES': 12 }

Answer 4

This should do the trick:

{" ".join(items[:-1]): items[-1]}