如何使用正则表达式 Notepad++ 提取 2 个模式之间的所有字符串？

Question

Extract all the string between 2 patterns:

Input:

test.output0    testx.output1    output3    testds.output2(\t)

Output:

output0    output1    ouput3   output2

Note: (" ") is the tab character.

Answer 1

You may try:

\.\w+$

Explanation of the above regex:

• \. - Matches . literally. If you do not want . to be included in your pattern; please use (?<=\.) or simply remove . .
• \w+ - Matches word character [A-Za-z0-9_] 1 or more time.
• $ - Represents end of the line.

You can find the demo of the regex in here.

Result Snap:

EDIT 2 by OP:

According to your latest edit; this might be helpful.

.*?\.?(\w+)(?=\t)

Explanation:

• .*? - Match everything other than new line lazily .
• \.? - Matches . literally zero or one time.
• (\w+) - Represents a capturing group matching the word-characters one or more times.
• (?=\t) - Represents a positive look-ahead matching tab .
• $1 - For the replacement part $1 represents the captured group and a white-space to separate the output as desired by you. Or if you want to restore tab then use the replacement $1\t .

Please find the demo of the above regex in here.

Result Snap 2:

Answer 2

Try matching on the following pattern:

Find: (?<![^.\s])\w+(?!\S)

Here is an explanation of the above pattern:

(?<![^.\s])  assert that what precedes is either dot, whitespace, or the start of the input
\w+          match a word
(?!\S)       assert that what follows is either whitespace of the end of the input

Demo