PHP 单元 - 模拟 Class

Question

How to mock class method getResult() ?

use App\ExampleClass;


$res = ExampleClass::getResult();

What I tried so far, and it didn't work:

$this->exampleClass = $this->getMockBuilder('App\ExampleClass')
    ->disableOriginalConstructor()
    ->getMock();


$this->exampleClass->expects($this->once())
    ->method('getResult')
    ->willReturn(true);

Answer 1

PHPUnit will ignore mocking static methods:

Please note that final, private, and static methods cannot be stubbed or mocked. They are ignored by PHPUnit's test double functionality and retain their original behavior except for static methods that will be replaced by a method throwing a \PHPUnit\Framework\MockObject\BadMethodCallException exception.

https://phpunit.readthedocs.io/en/9.2/test-doubles.html?highlight=static#test-doubles

You can't do it with PHPUnit's phpunit-mock-objects library. Seek to the alternative - Mockery :

$this->exampleClassMock = \Mockery::mock('overload:App\ExampleClass');

$this->exampleClassMock
  ->shouldReceive('getResult')
  ->once()
  ->andReturn(true);