如何在 7 位上将字符串转换为二进制？ (JavaScript)

Question

I need to convert a string to binary specifically on 7 bits.

'%'.charCodeAt().toString(2)

The above code return 100101, I think it convert on 8 bits. (so this link How to convert text to binary code in JavaScript? is not helping me).

% is equal to 0100101 in binary on 7 bits.

The only links I found on SO are about Java.

Answer 1

You can try this with the help of String.prototype.patStart()

 const sevenBitBinary = (char) => char.charCodeAt().toString(2).padStart(7, '0'); console.log(sevenBitBinary('%'));

Answer 2

You can add 0s add the beginning with .padStart .

Answer 3

I think it can help you

 function get7BitsBinaryString(number) { var result = ''; var bits = [64, 32, 16, 8, 4, 2, 1]; bits.forEach(bit => { if ((bit & number) === bit) { result += '1'; } else { result += '0'; } }); return result; } console.log(get7BitsBinaryString('%'.charCodeAt()));