正则表达式查找与特定模式匹配的行

Question

I have a txt file and it has the data has a /////////// to divide the results. I need to find the results that only have 1 line.

I've tried but I can't seem to figure out how to differentiate the multiple lines between the ///////////

For example, I just need to find the a and the d.

/////////// 
a
///////////
b
c
//////////
d
/////////

Answer 1

This will pull the letters you need into a capturing group:

\/+\s+(\S+)\s+(?=\/+)

Explanation:

• At least one / , followed by
• At least one whitespace \s (includes newlines), followed by
• At least one non-whitespace character \S , followed by
• At least one whitespace \s , and
• At least one / , in a positive lookahead group

Demo: https://regex101.com/r/pHg9ov/3

Answer 2

• Ctrl + F
• Find what: ^/+\R\K.+(?=\R/+$)
• CHECK Wrap around
• CHECK Regular expression
• UNCHECK . matches newline . matches newline
• Find All in Current Document

Explanation:

^           # beginning of line
  /+        # 1 or more slashes
  \R        # any kind of linebreak
\K          # reset match
.+          # 1 or more any character but newline
(?=         # positive look ahead, make sure we have after:
  \R          # any kind of linebreak
  /+          # 1 or more slashes
  $           # end of ine
)           # end look ahead

Screenshot (before):

Screenshot (after):