等待 function 完成

Question

I have structure like:

function1 ()
{
A;
function2(){};
B;
}

How can i force function2 return result then run B? it always A->B->function2

Appreciate any comments. Paxton.

Answer 1

Your question is answer, if the function is not async.

function a() {
  console.log('a');
  function b() {
    console.log('b');
  }
  b();
}
a();