javascript 过滤字符串数组，匹配不区分大小写的 substring

Question

I have an array of names filtered by a certain string. How can I match all names that include this string, but insensitive of case?

this.employeeDisplayList = this.employeeList.filter(e => e.employeeName.includes(this.searchStr));

Answer 1

this.employeeDisplayList = this.employeeList.filter(e => {
    const emp = e.employeeName.toLowerCase();
    const str = this.searchStr.toLowerCase();
    return emp.includes(str);
});

Answer 2

You can just apply .toLowerCase() to both the employeeName and the searchString.

 let employeeDisplayList = [{employeeName: "Jules 1"}, {employeeName: "jules 2"}, {employeeName: "Max"}]; let searchStr = "Jules"; console.log(employeeDisplayList.filter(e => e.employeeName.toLowerCase().indexOf(searchStr.toLowerCase()) >= 0));

Another way would be to search with a case insensitive regex: string.match(/word/i)