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Django,在 settings.py 中管理调试标志

[英]Django, managing debug flag in settings.py

Say you have说你有

  • base_settings.py base_settings.py
  • debug_settings.py调试设置.py
  • product_settings.py product_settings.py

in debug_settings.py在 debug_settings.py

DEBUG = True
from base_settings import *

in product_settings.py在 product_settings.py

DEBUG = False
from base_settings import *

in base_settings.py在 base_settings.py

# this condition check is problamatic, I don't think I can define DEBUG variable outside of `base_settings.py` ?
if DEBUG:
   foo()

How do you have a common base_settings.py which has conditional code dependant on variable (DEBUG) whose value can be changed from the importing module?您如何拥有一个通用的 base_settings.py,它的条件代码取决于变量(DEBUG),其值可以从导入模块中更改? (from debug_settings, product_settings) (来自 debug_settings、product_settings)

A better way to do this would be to use environment variables更好的方法是使用环境变量

in debug_settings.py:在 debug_settings.py 中:

os.environ["DEBUG"] = "TRUE"

in product_settings.py:在 product_settings.py 中:

os.environ["DEBUG"] = "FALSE"

then in base_settings.py:然后在 base_settings.py 中:

if os.getenv("DEBUG", "TRUE"): #The second argument specifies the default in case "DEBUG" has not been set
    foo()

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