[英]Sum of values of nested dictionary
I have a sum of all values of nested dictionary with variable number of elements: For example:-我有元素数量可变的嵌套字典的所有值的总和:例如:-
a = {'val1': 3, 'val2': 4, 'val3': {'val4': 2, 'val5': 1}, 'val6': {'val7': 9, 'val8': {'val6': 43}}}
Let say I have a dictionary like above.假设我有一本像上面这样的字典。 And the output I want for this is:我想要的 output 是:
3+4+2+1+9+43 = 62
I have tried this but I know it will not work:我已经尝试过了,但我知道它不起作用:
dict_sum = 0
for k, v in a.items():
if isinstance(v,dict):
dict_sum += sum(v.values())
else:
dict_sum += v
But it will not work work for dictionary with multiple nested dictionaries.但它不适用于具有多个嵌套字典的字典。 Any help would be appreciated.任何帮助,将不胜感激。
One approach is using recursion.一种方法是使用递归。
For example:例如:
data = {'val1': 3, 'val2': 4, 'val3': {'val4': 2, 'val5': 1}, 'val6': {'val7': 9, 'val8': {'val6': 43}}}
def get_sum(data):
s = 0
for _, v in data.items():
if isinstance(v, dict):
s += get_sum(v)
else:
s += v
return s
print(get_sum(data)) # --> 62
Using list comprehension使用列表理解
a = {'val1': 3, 'val2': 4, 'val3': {'val4': 2, 'val5': 1}, 'val6': {'val7': 9, 'val8': {'val6': 43}}}
def DeepSum(data):
return sum([x if isinstance(x, int) else DeepSum(x) for x in data.values() ])
DeepSum(a)
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