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单体型 class

[英]The Monoid type class

I am trying to play around with monoids in Haskell, using this page: https://en.wikibooks.org/wiki/Haskell/Monoids .我正在尝试在 Haskell 中使用幺半群,使用此页面: https://en.wikibooks.org/wiki/Haskell/Monoids I entered the following information in the terminal (after importing Data.Monoid ):我在终端中输入了以下信息(在导入Data.Monoid之后):

class Monoid a where
    mempty  :: a
    mappend :: a -> a -> a
    mconcat :: [a] -> a
    mconcat = foldr mappend memptyhere
newtype Sum a = Sum { getSum :: a }
instance Num a => Monoid (Sum a) where
     mempty = Sum 0
     Sum x `mappend` Sum y = Sum (x + y)

However, when I then try Sum 5 <> Sum 6 <> Sum 10 , I receive the following message:但是,当我尝试Sum 5 <> Sum 6 <> Sum 10时,我收到以下消息:

<interactive>:115:1: error:
• Non type-variable argument in the constraint: Semigroup (Sum a)
  (Use FlexibleContexts to permit this)
• When checking the inferred type
    it :: forall a. (Semigroup (Sum a), Num a) => Sum a

I don't understand what errors these are, and why Sum 5 <> Sum 6 <> Sum 10 didn't work.我不明白这些是什么错误,以及为什么Sum 5 <> Sum 6 <> Sum 10不起作用。

The problem is that you are using your own Sum type and Monoid type class with an operator <> that is not the same function as your version of mappend .问题是您使用自己的Sum类型和Monoid类型 class 和运算符<>与您的 mappend 版本不同mappend If you were to enter this program in a multi-line GHCi prompt:如果您要在多行 GHCi 提示符中输入此程序:

> :{
Prelude| ...paste your program in here...
Prelude| :}
>

and then try this instead:然后试试这个:

> Sum 5 `mappend` Sum 6 `mappend` Sum 7
Sum 5 `mappend` Sum 6 `mappend` Sum 7 :: Num a => Sum a

there would be no error.不会有错误。 If you added a deriving (Show) to your Sum type, you'd even get the answer you're looking for!如果您在Sum类型中添加了deriving (Show) ,您甚至会得到您正在寻找的答案!

Ok, modules loaded: none.
λ> :{
Prelude| class Monoid a where
Prelude|     mempty  :: a
Prelude|     mappend :: a -> a -> a
Prelude|     mconcat :: [a] -> a
Prelude|     mconcat = foldr mappend mempty
Prelude| newtype Sum a = Sum { getSum :: a } deriving (Show)
Prelude| instance Num a => Monoid (Sum a) where
Prelude|      mempty = Sum 0
Prelude|      Sum x `mappend` Sum y = Sum (x + y)
Prelude| :}
λ> Sum 5 `mappend` Sum 6 `mappend` Sum 7
Sum {getSum = 18}
λ> 

The rules for overriding library definitions in GHCi can be a little complicated, so it might be a better idea to put this into a xxx.hs file and load it into GHCi with :l xxx.hs for testing.在 GHCi 中覆盖库定义的规则可能有点复杂,因此最好将其放入xxx.hs文件并使用:l xxx.hs将其加载到 GHCi 中进行测试。 If you'd tried to load this program as a xxx.hs file, you would have gotten much clearer messages about the problem:如果您尝试将此程序作为xxx.hs文件加载,您会得到关于该问题的更清晰的消息:

MonoidExample2.hs:7:19-24: error:
    Ambiguous occurrence ‘Monoid’
    It could refer to
       either ‘Prelude.Monoid’,
              imported from ‘Prelude’ at MonoidExample2.hs:1:1
              (and originally defined in ‘GHC.Base’)
           or ‘Main.Monoid’, defined at MonoidExample2.hs:1:1

Then, you could use the special import Prelude syntax to hide the library definitions you didn't want.然后,您可以使用特殊的import Prelude语法来隐藏您不想要的库定义。 The following version works as a self-contained program:以下版本作为独立程序工作:

import Prelude hiding (Monoid, mempty, mappend, mconcat, (<>))

class Monoid a where
  mempty  :: a
  mappend :: a -> a -> a
  mconcat :: [a] -> a
  mconcat = foldr mappend mempty

newtype Sum a = Sum { getSum :: a } deriving (Show)

instance Num a => Monoid (Sum a) where
  mempty = Sum 0
  Sum x `mappend` Sum y = Sum (x + y)

(<>) :: Monoid a => a -> a -> a
(<>) = mappend

main :: IO ()
main = print $ Sum 5 <> Sum 6 <> Sum 10

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