[英]How to convert this whole column into date format?
I tried this to remove the unwanted characters but it is not working我试过这个来删除不需要的字符,但它不起作用
from datetime import datetime
dates = []
for i in data.Date:
date_time_str = str(data.Date[i])
date_time_str = date_time_str.replace("M ","")
date1 = date_time_str.replace(".","")
dates.append(date1)
print(dates)
Use pd.to_datetime and give a correct format string for your data ( 'M %m.%Y'
):使用pd.to_datetime并为您的数据提供正确的格式字符串(
'M %m.%Y'
):
import pandas as pd
data = pd.DataFrame( {"Code":[114, 115, 116, 117],
"Date":["M 02.2017", "M 03.2018", "M 04.2019", "M 05.2020",]})
print(data)
# simply use the correct format string for your data here
data["asDate"] = pd.to_datetime(data["Date"], format = "M %m.%Y")
print(data)
Output: Output:
Code Date
0 114 M 02.2017
1 115 M 03.2018
2 116 M 04.2019
3 117 M 05.2020
Code Date asDate
0 114 M 02.2017 2017-02-01
1 115 M 03.2018 2018-03-01
2 116 M 04.2019 2019-04-01
3 117 M 05.2020 2020-05-01
To get just the dates as list use仅获取日期作为列表使用
dates_1 = list(data["asDate"]) # contains <class 'numpy.datetime64'> and
dates_2 = list(data["asDate"].values) # <class 'pandas._libs.tslibs.timestamps.Timestamp'>
Assuming your dates are always prefaced with 'M '
(meaning that the actual date starts at position 2 in the string):假设您的日期总是以
'M '
开头(意味着实际日期从字符串中的 position 2 开始):
df['date'] = df['date'].apply(lambda x: pd.to_datetime(x[2:], format = '%m.%Y'))
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