从列表中随机打印 integer 编号 python

Question

i have this little bit problem where after i generate random number to a list of 50 when i input the same number on the list, it does not print "match found". it will always send me "no match found". can you guys explain what is wrong with the code.

import random

mylist=[]

for i in range (50):
 x= random.randint(100,999)
 mylist.append(x)

print(mylist)

p = input('Enter an integer number: ')

for i in range(len(mylist)):
    if p == mylist[i]:
        print('Match found at position')
        break
else:
    print('no match found')

example of output

[836, 569, 378, 788, 847, 584, 404, 159, 362, 271, 151, 100, 702, 414, 867, 213, 194, 553, 946, 930, 777, 143, 143, 879, 724, 752, 431, 416, 944, 509, 752, 211, 713, 951, 882, 836, 710, 998, 447, 892, 720, 210, 364, 768, 603, 456, 540, 727, 346, 153]
Enter an integer number: 836
no match found
>>> 

i just started learning coding so if u guys can explain it i would be happy to understand for future reference:)

Answer 1

typecast your input with int() then print index that match

import random

mylist=[]

for i in range (50):
 x= random.randint(100,999)
 mylist.append(x)

print(mylist)

p = input('Enter an integer number: ')

for i in range(len(mylist)):
    if int(p) == mylist[i]:
        print('Match found at position ' + str(i))
        break
    else:
        print('no match found')

Answer 2

On top of correcting the type cast mentioned in comments, you do not even need a loop to find the match. Use the powerful in in python. You can replace your entire search loop with this:

if int(p) in mylist:
    print('Match found at position')
else:
    print('no match found')

And if you need to print the index of p in the list, use this:

try: 
  print('Match found at position ',mylist.index(int(p)))
except:
  print('no match found')

And you can use numpy package to create a list of random integers without loop as well:

import numpy as np
mylist = np.random.randint(100, high=999, size=50).tolist()

So your entire code will look like this:

import numpy as np

mylist = np.random.randint(100, high=999, size=50).tolist()
p = input('Enter an integer number: ')
if int(p) in mylist:
    print('Match found at position')
else:
    print('no match found')