在 dataframe 的字符串中查找 substring 的索引

Question

I have a dataframe with two columns (and alot of rows), one column is the full sequence the other contains a sub sequence.

I want to find the index of where the sub sequence starts within the full sequence and add this as a another column:

I have tried this:

df["start"] = df.sequence.index(df.sub_sequence)

But this returns: TypeError: 'RangeIndex' object is not callable

What am i doing wrong?

Heres the df and the df i wish to end up with:

Sample dataframe:

import pandas as pd 

data = {"sequence": ["abcde","fghij","klmno"], "sub_sequence": ["cde", "gh", "no"]}    
df = pd.DataFrame (data, columns = ['sequence','sub_sequence'])

  sequence sub_sequence
0    abcde          cde
1    fghij           gh
2    klmno           no

---

Expected result:

data2 = {"sequence": ["abcde","fghij","klmno"], "sub_sequence": ["cde", "gh", "no"], "start": [2,1,3]}
df2 = pd.DataFrame (data2, columns = ['sequence','sub_sequence','start'])

  sequence sub_sequence  start
0    abcde          cde      2
1    fghij           gh      1
2    klmno           no      3

Answer 1

Use zip andstr.index in a list comprehension:

df['start'] = [seq.index(sub) for seq, sub in zip(df['sequence'], df['sub_sequence'])]

OR Use DataFrame.apply along axis=1 +str.index :

df['start'] = df[['sequence', 'sub_sequence']].apply(lambda s: str.index(*s), axis=1)

Result:

  sequence sub_sequence  start
0    abcde          cde      2
1    fghij           gh      1
2    klmno           no      3