错误：一元'*'的无效类型参数（有'int'）

Question

#define NVIC_IPR_BASEADDR          (volatile)((uint32_t *)0XE000E400)

#define No_PR_Bits_Implemented     4

void GPIO_IRQPriorityConfig(uint8_t IRQNumber, uint8_t IRQPriority); 

int main(void)
{

void GPIO_IRQPriorityConfig(uint8_t IRQNumber, uint8_t IRQPriority) 

{

    //1. First lets find out the IPR register.

    uint8_t iprx= IRQNumber/4;
    uint8_t iprx_section= IRQNumber%4;
    uint8_t shift_amount = (8 * iprx_section) + (8- No_PR_Bits_Implemented);

    *(NVIC_IPR_BASEADDR + iprx * 4 ) |= (IRQPriority << shift_amount); //error line

}

}

Answer 1

#define NVIC_IPR_BASEADDR          (volatile)((uint32_t *)0XE000E400)

That does not result in a pointer type. The outer (volatile) has no explicit type and will thus result in the type defaulting to int . With gcc for example, should get a warning similar to the following:

warning: type defaults to ‘int’ in type name [-Wimplicit-int]

The correct define should be:

#define NVIC_IPR_BASEADDR          ((volatile uint32_t *)0XE000E400)