typescript - 有没有办法从类型定义创建一个实例

Question

Using Typescript, I am trying to create a DI system, and I want to use the type (or interface ) as the key.

For example,

interface IMath {
  add: (a: number, b: number) => number;
  sub: (a: number, b: number) => number;
}

class Math implements IMath {
  add(a: number, b: number) { return a + b };
  sub(a: number, b: number) { return a - b };
}

di.register(IMath, Math); // of course this doesn't work

This is is possible in runtime-typed languages, like C#, where types are in-memory (which we don't want).
In typescript, all type data is removed before ever reaching runtime.

My question is - can we create an object or symbol, that will represent the type during runtime?

const mathId = typeToId<IMath>();
// "c8393b569dbae9ed04e5b22d9c2e6fb7"

const mathStub = typeToStub<IMath>();
// { add: () => 0, sub: () => 0 }

Answer 1

A similar project I found was flow-runtime , using babel-plugin-flow-runtime . (There's also a TS equivalent called TS-runtime, but it doesn't seem as developed)

type User = {
  id: number;
  name: string;
};

transforms into

import t from 'flow-runtime';
const User = t.type('User', t.object(
  t.property('id', t.number()),
  t.property('name', t.string())
));

This seems like an overkill, both in bundle size and performance.
I also tried it in one of my projects still using Flow, and it's giving mixed results.