如何使用 python 单击位于 selenium 下的无线电输入角色

Question

I am doing some automation script for the website https://silkdb.bioinfotoolkits.net in selenium using python language where I have you can see a button named "Blast" that pops up a window with some default values on click.

<div data-meta="Field" id="program" role="radiogroup" class="next-radio-group next-radio-button next-radio-button-medium">
<label dir="ltr" aria-checked="true" class="next-radio-wrapper checked "><span class="next-radio-single-input">
   <input role="radio" tabindex="0" type="radio" aria-checked="true" class="next-radio-input"></span><span class="next-radio-label">blastn</span>
</label>

<label dir="ltr" aria-checked="false" class="next-radio-wrapper "><span class="next-radio-single-input">
<input role="radio" tabindex="-1" type="radio" aria-checked="false" class="next-radio-input"></span><span class="next-radio-label">blastx</span></label>

<label dir="ltr" aria-checked="false" class="next-radio-wrapper "><span class="next-radio-single-input"><input role="radio" tabindex="-1" type="radio" aria-checked="false" class="next-radio-input"></span><span class="next-radio-label">tblastn</span></label>

<label dir="ltr" aria-checked="false" class="next-radio-wrapper "><span class="next-radio-single-input"><input role="radio" tabindex="-1" type="radio" aria-checked="false" class="next-radio-input"></span><span class="next-radio-label">blastp</span></label></div>

The default label named "blastn" is selected on defualt. But I want to select lable named "blastp".

I have tried many things using xpath but I am unable to get it selected.

Please help me in this.

Answer 1

To click on the element you have to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies :

• Using CSS_SELECTOR :

   driver.get("https://silkdb.bioinfotoolkits.net/") WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button#btn-blast"))).click() WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "div#program label:last-child span:nth-child(2)"))).click()

• Using XPATH :

   driver.get("https://silkdb.bioinfotoolkits.net/") WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//button[@id='btn-blast']"))).click() WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//span[@class='next-radio-label' and text()='blastp']"))).click()

• Note : You have to add the following imports:

   from selenium.webdriver.support.ui import WebDriverWait from selenium.webdriver.common.by import By from selenium.webdriver.support import expected_conditions as EC

Browser Snapshot:

Answer 2

It is important to send the click events to the appropriate receiving elements which can actually react to the click event. In this case, i think the click must be send to the input element, not the span. Please try with the following xpath.

//span[@class="next-radio-label" and contains(text(),'blastp')]/preceding-sibling::span/input

Answer 3

Please use following xpath to click your option //span[contains(text(),'blastp')]