[英]How can I use a for loop to create an array and assign linear values?
I want to create an array and using a for loop and I want to assign values with an increment of 1o.我想创建一个数组并使用 for 循环,我想以 1o 的增量分配值。 So far here is what I have and I am not getting the result I want...
到目前为止,这就是我所拥有的,但我没有得到我想要的结果......
public class ArrayDemo1 {
public static void main(String[] args) {
int array[] = new int[10];
System.out.println("The array elements are: ");
for (int i = 0; i <= array.length - 1; i++) { // Controls index...
for (int j = 0; j < 101; j += 10) { // Controls value of each array index...
array[i] = j;
System.out.println(array[i]);
}
}
}
}
Here is my output [Stack overflow won't let me have the whole output so here is the shortened version;这是我的 output [堆栈溢出不会让我拥有整个 output 所以这是缩短的版本; This output (starting at /* and ending at */) was repeated 10 full times.
这个 output(从 /* 开始到 */ 结束)重复了 10 次。 It printed from 0 to 100 ten times with an increment of 10]:
它以 10 为增量从 0 到 100 打印十次]:
The array elements are:
/*
0
10
20
30
40
50
60
70
80
90
100
*/
Process finished with exit code 0
Here is what I want.这就是我想要的。 For every index, I want one value and the next value should be an increment of 1o:
对于每个索引,我想要一个值,下一个值应该是 1o 的增量:
The array elements are:
0
10
20
30
40
50
60
70
80
90
You don't need a nested for loop to assign values into a single array.您不需要嵌套的 for 循环将值分配给单个数组。
Populate each index by i*10
rather than introduce j
.用
i*10
填充每个索引,而不是引入j
。
You should also print the array in a new loop, otherwise, there's not much purpose for keeping the array and printing it in the same location您还应该在新循环中打印数组,否则,将数组保留并打印在同一位置没有太大意义
And rather than <= array.length - 1
, you'll want < array.length
而不是
<= array.length - 1
,你会想要< array.length
You can also use an IntStream
, which is the modern way to achieve the same result您还可以使用
IntStream
,这是实现相同结果的现代方式
You don't need a nested loop - the value is always the index multiplied by 10:您不需要嵌套循环 - 值始终是索引乘以 10:
for (int i = 0; i <= array.length - 1; i++) {
array[i] = i * 10;
}
EDIT:编辑:
If you don't have to use loops, this could arguably be done more elegantly with a stream:如果您不必使用循环,则可以使用 stream 更优雅地完成此操作:
int[] array = IntStream.range(0, 10).map(i -> i * 10).toArray();
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