如何从 Azure DevOps 管道读取 Azure 文件共享文件

Question

I currently have created an Azure storage account. Inside of this storage, I've created two file shares. I've uploaded files into each file share, and would like to access these files from within the Azure DevOps pipeline.

I've researched online how to do this, and have not found a resource detailing how to do this. Has anyone done this before? If yes, what are the steps to read file share files from an azure devOps pipeline?

Thanks.

People asked

Answer 1

would like to access these files from within the Azure DevOps pipeline

You could try to use AzCopy command to copy/download those two file shares from Azure blob to Azure DevOps Pipeline:

azcopy login
azcopy copy /Source:https://myaccount.file.core.windows.net/myfileshare/myfolder/ /Dest:$(Build.SourcesDirectory)\myfolder

You can find more info in this document:

Quickstart: Upload, download, and list blobs with PowerShell

Answer 2

I found a solution using the Microsoft Azure File Share Storage Client Library for Python . I ran the following steps inside of my Azure pipeline to connect to my File Share. Below is an example that connects to the file share and shares all its contents:

    - task: UsePythonVersion@0
      displayName: 'Set Python 3.8.3'
      inputs:
        versionSpec: 3.8.3
        addToPath: true
      name: pyTools

    - script: $(pyTools.pythonLocation)/bin/pip3 install azure-storage-file-share
      displayName: Install azure-storage-file-share module
        
    - task: PythonScript@0
      displayName: Show files and directories inside of File Share
      inputs:
        scriptSource: 'inline'
        script: |
          import platform
          from azure.storage.fileshare import ShareDirectoryClient

          connection_string = "DefaultEndpointsProtocol=https;AccountName=<storage-name>;AccountKey=<access-key>==;EndpointSuffix=core.windows.net"
          parent_dir = ShareDirectoryClient.from_connection_string(conn_str=connection_string, share_name=<file-share-name>, directory_path="")

          my_list = list(parent_dir.list_directories_and_files())
          print(my_list)
          print(platform.python_version()