从另一个 python 脚本运行 python 脚本

Question

i have a test script test.py inside which i am trying to run one more python script bexec.app (this is a python script). Actually test.py is just for my testing. The original script is a lengthy one and bexec.app is getting called inside in a command line.

I tried this

#!/usr/bin/python
import os, sys
os.path.insert(0, 'current bexec script path')
import bexec.app

But this does not work -

Traceback (most recent call last):
  File "test", line 5, in <module>
    import bexec.pphshaper
ImportError: No module named bexec.app

I donot want to change the bexec.app script to bexec_app.py because this follows some naming convention

bexec.app also has #!/usr/bin/python inside it. how can i import my bexec script inside test.py

Answer 1

You seem to want to run your bexec, not import it. And if so, regular

os.system('current bexec script path')

should be sufficient

Answer 2

Dot means subpackage structure to python, but it's still possible with imp .

below is bexec.app sample file:

#!/usr/bin/python

a = 2

and this is how you can import it in your test.py file, look below for the code:

#!/usr/bin/python
import os, sys, imp

my_module = imp.load_source('my_module', 'bexec.app')

print (my_module.a)