python 中的正则表达式拆分字符串

Question

I have a string like this

SELECT [Orders$].[Category] AS [Category],&#13,&#10,  [Orders$].[City] AS [City],&#13,&#10,  [Orders$].[Country] AS [Country],&#13,&#10,  [Orders$].[Customer ID] AS [Customer ID],&#13,&#10,  [Orders$].[Customer Name] AS [Customer Name],&#13,&#10,  [Orders$].[Discount] AS [Discount],&#13,&#10,  [Orders$].[Profit] AS [Profit],&#13,&#10,  [Orders$].[Quantity] AS [Quantity],&#13,&#10,  [Orders$].[Region] AS [Region],&#13,&#10,  [Orders$].[State] AS [State],&#13,&#10,  [People$].[Person] AS [Person],&#13,&#10,  [People$].[Region] AS [Region (People)]&#13,&#10,FROM [Orders$]&#13,&#10,  INNER JOIN [People$] ON [Orders$].[Region] = [People$].[Region]

I want to get only Category and city dynamically without hardcoding the word. What kind of pattern should i use?? So that i will store those two values in an array which is looped in downstream program.

I tried splitting the text

colName = re.split("\W+", result)

['SELECT',
 'Orders',
 'Category',
 'AS',
 'Category',
 '13',
 '10',
 'Orders',
 'City',
 'AS',
 'City',
 '13',
 '10',

it gave me the whole string, now do not know how to proceed. Can someone help??

Thanks

Answer 1

Don't use split, use re.findall() .

matches = re.findall(r'\bAS\s+\[(.+?)\]', yourString)

The words you want are in group(1) of each match in matches .

Answer 2

Not sure if I understand your question correctly, seems you can simply continue with:

>>> category = colName[2]
>>> city = colName[8]

You can print to check:

>>> print(category, city)
Category City