如何在 Oracle SQL 中找到 col 有字母、数字或特殊字符（连字符、撇号和空格除外）的行

Question

I have to find the name like: Robert@jr23 (There must be Alphabet,Any Special characters or Numbers except hyphen(-),apostrophe (') and Space).

I was doing as below:

select * from test where REGEXP_LIKE(trim(NAME_1), '[^- '']')

But I am not getting the right results with this.

Need to match:

Kevin#123
bob@jr
mike$dr

Needs to exclude:

Alex-jr
Robert'jr
Brian jr

Answer 1

You need to use not with a pattern matching the values you want to exclude. Otherwise you are matching strings that contain any character that is not in the exclusion list, which is all of them.

select column_value
from   ora_mining_varchar2_nt
       ( 'Kevin#123'
       , 'bob@jr'
       , 'mike$dr'
       , 'Alex-jr'
       , 'Robert''jr'
       , 'Brian jr'
       , 'A!' )
where  1=1
and    not regexp_like(column_value,'[- '']')
and    regexp_like
       (column_value, '([A-Z0-9]+[^A-Z0-9])|([^A-Z0-9]+[A-Z0-9])', 'i') ;

Edit: added a regex_like condition to ensure that values contain a letter or digit and a 'special character', meaning here a character that is neither a letter, digit or space, ' or - .

Answer 2

One option is to replace everything that's valid with NULL , and what remains is invalid :

SQL> with test (col) as
  2    (select 'Robert@jr23' from dual union all
  3     select 'Kevin#123'   from dual union all
  4     select 'bob@jr'      from dual union all
  5     select 'mike$dr'     from dual union all
  6     select 'Alex-jr'     from dual union all
  7     select 'Robert''jr'  from dual union all
  8     select 'Brian jr'    from dual
  9    )
 10  select col
 11  From test
 12  where regexp_replace(col, '[[:alpha:]]|[[:digit:]]|-|''', null) is not null;

COL
-----------
Robert@jr23
Kevin#123
bob@jr
mike$dr
Brian jr

SQL>

---

I'm confused about what you, actually, want to get as a result. Here are some examples which show result of such a regular expression; which IDs do you want to get as a result?

SQL> with test (id, col) as
  2    (select 1, 'Robert@jr23' from dual union all
  3     select 2, 'Kevin#123'   from dual union all
  4     select 3, 'bob@jr'      from dual union all
  5     select 4, 'mike$dr'     from dual union all
  6     select 5, 'Alex-jr'     from dual union all
  7     select 6, 'Robert''jr'  from dual union all
  8     select 7, 'Brian jr'    from dual union all
  9     select 8, 'Brian10'     from dual
 10    )
 11  select col,
 12  regexp_replace(col,
 13    '[[:alpha:]]|[[:digit:]]|[[:space:]]|-|''', null) result
 14  from test;

COL         RESULT
----------- ----------
Robert@jr23 @
Kevin#123   #
bob@jr      @
mike$dr     $
Alex-jr
Robert'jr
Brian jr
Brian10

8 rows selected.

SQL>

---

One of your comments says:

select a customer name where there must be a special character or numbers (except space, Hyphen and apostrophe)

which means that numbers and special characters should be treated as "equal". If that's so, does this help?

SQL> with test (id, col) as
  2    (select 1, 'Robert@jr23' from dual union all
  3     select 2, 'Kevin#123'   from dual union all
  4     select 3, 'bob@jr'      from dual union all
  5     select 4, 'mike$dr'     from dual union all
  6     select 5, 'Alex-jr'     from dual union all
  7     select 6, 'Robert''jr'  from dual union all
  8     select 7, 'Brian jr'    from dual union all
  9     select 8, 'Brian10'     from dual
 10    )
 11  select id, col
 12  from test
 13  where regexp_replace(col, '[[:alpha:]]|[[:space:]]|-|''', '')
 14    is not null;

        ID COL
---------- -----------
         1 Robert@jr23
         2 Kevin#123
         3 bob@jr
         4 mike$dr
         8 Brian10

SQL>

Answer 3

You can use following query to include all special characters except space, - and '

SQL> with tbl(name) as (
  2        select 'Kevin#123'          from dual union
  3        select 'bob@jr' from dual union
  4        select 'mike$dr' from dual union
  5        select 'Alex-jr'         from dual union
  6    select 'Brian jr'         from dual union
  7    select 'Brian)jr'         from dual union
  8        select 'Robert''jr'  from dual
  9      )
 10      select *
 11      from tbl
 12      where regexp_like(name, '[^[a-z]|[A-Z]|[:space:]|[:cntrl:]|/]')
 13  and  not regexp_like(name,'[- '']');

NAME
---------
Brian)jr -- see this is included
Kevin#123
bob@jr
mike$dr

SQL>