C# - 设置新创建的 xml 文件的构建操作的代码

Question

I have code that creates a new Xml file and then I simply save it to a location in another project. My question is, is there code that I can write so that:

1. My file gets included in my project.

2. Build Action gets set to Content.

3. Set "Copy to Output Directory" to "Copy Always".

Any help is appreciated. Thanks.

Answer 1

Try this... You may find better approaches possibly, but this one isn't bad (for me) and should work.

The settings outlined in the question are typically entries in the project file (.csproj). Try editing the.csproj file on the target location and add the entries.

You will have to first search for a tag in csproj XML file, with tag name <ItemGroup> that has child tag(s) with name <Content> . If you do not find any, add an <ItemGroup> when you write your xml entries to the proj file. If you find one, just add the tage part in the below string to that ItemGroup tag.

@"<ItemGroup>" + // Add this parent node only if you do not find an existing one as mentioned above
"<Content Include="MyXmlFileNameWithExtemsionAndPath.xml">" +
"<CopyToOutputDirectory>Always</CopyToOutputDirectory></Content>" +
"</ItemGroup>" // Add this only if you do not find an existing one as mentioned above