HLA程序是死循环？

Question

So the program I'm trying to write in HLA should do the dollowing: I enter a digit, and it gives a pattern of numbers. The pattern should show all the odd numbers from 1 up to that number followed by all the even numbers from 2 up to that number. Here is my code:

program boxit; 
#include ("stdlib.hhf"); 
static iDatavalue : int8 := 0 ; 


Begin boxit; 

    stdout.put("Gimme a decimal value to use as n: "); 

    stdin.get(iDatavalue); 
    mov(iDatavalue, BH); 
DoWhileLp:
DoWhileLpBody:
ForLp:
InitializeForLp:
    mov(BH, CH); 
ForLpTerminationTest:
    cmp(CH, 0); 
    jnl ForLpDone; 
ForLpBody:
    stdout.put("I = ", CH, nl); 
ForLpIncrement:
    dec(CH); 
    jmp ForLpTerminationTest; 
ForLpDone:
    dec(CH); 
DoWhileLpTermination:
    cmp(CH, 0); 
    jbe DoWhileLpDone; 
    jmp DoWhileLpBody; 
DoWhileLpDone:
    stdout.puti8(BH); 

end boxit;

However, it is a infinite loop and I'm not sure how to solve this issue.

I Highly appreciate any and all help!

Answer 1

ENVIRONMENT

• HLA (High Level Assembler - HLABE back end, LD linker) Version 2.16 build 4409 (prototype)
• Ubuntu 20.04.1

NOTE

• As mentioned in previous comments:
  • Nested loops using the same loop control variable is poor design and leads to hard to debug problems such as an infinite loop.
  • This assignment is more simply solved using two sequential loops instead of nested loops.
  • Starting with a higher level language to design the algorithm is good practice. The following example provides a working solution using the higher level functionality of HLA which is a good starting point to work towards assembly.

EXAMPLE

program Boxit;
#include ("stdlib.hhf");

begin Boxit;
    stdout.put("Gimme a decimal value to use as n: ");
    stdin.geti32();

    for ( xor(EBX, EBX); EBX <= EAX; add(2, EBX) ) do
        stdout.puti32(EBX);
        stdout.put(", ");
    endfor;

    stdout.newln();

    for ( mov(1, EBX); EBX <= EAX; add(2, EBX) ) do
        stdout.puti32(EBX);
        stdout.put(", ");
    endfor;

end Boxit;