通过关系从类别 id 获取类别名称。 Laravel

Question

I have looked through the forum, but the solutions I have seen so far, aren't aligning with the issues I'm getting, so, I was hoping someone more informed would help out.

So I have a Category modem and A post model and there relationship is as follows;

on post model:

public function postcategory(){
    return $this->belongsTo(PostCategory::class);
}

on category model:

public function posts(){
    return $this->hasMany(Post::class)->where('approved', 'true');
}

and I am using slugs to retrieve all the posts that belongs to a certain category slug, using this function:

public function cats($category){
    $posts = PostCategory::where('category_slug', $category)->first()->posts;
    $category = PostCategory::where('category_slug', $category)->first();
    return view('posts', compact('posts', 'category')); 
}

Now, I am trying to get the name of the category with the category id stored in the posts table. for example, if I have a category id of 1 and on the category table, if the id number 1 is PHP, how do I return the name PHP instead of the id 1?

Secondly, if I wanted to paginate the view where posts is being compacted to, how do I do that? I switched the code in the controller to this:

$posts = PostCategory::with('posts')->where('category_slug', $category)->paginate(15);

when I dd that line of code, it returns some values (with relations), but when I pass that to the view, I get errors.

Hopefully, someone see this and help me out. :D

Answer 1

on Category Model:

public function posts()
{
    return $this->hasMany(Post::class);
}

On Controller:

public function cats($slug)
{
    $category = PostCategory::whereSlug($slug)->firstorFail();
    $posts= $category->posts()->where('approved', 'true')->paginate(15);
    return view('category.show', compact('posts', 'category'));
}

On View:

@foreach($posts as $post)
 $post->title
 ....
@endforeach
{{ $posts->links() }}