从 makefile 运行 a.tcl 命令

Question

I am new to writing a makefile which will be executed on a linux machine.

I have the following tasks to do in a makefile: 1)check if the files in the path/directory are exists and modified recently 2)run a.tcl file

I have written the following piece of code..can you please help me. PATH =/work/source/

task1:
    ifeq (,$(PATH))
         @echo "error file does not exist!"
    endif

    #check for files modified
    
    #run the .tcl command
    run evaltest.tcl


reports :@echo "reports tbd"


.PHONY : all 
 all: task1 reports

Please let me know what changes are required for it to run as expected.

Answer 1

You seem to be planning to do way too much work yourself. Your task #1 is typically what make does. So that only leaves task #2. If a Tcl script has the excutable permission and starts with a valid hashbang, you can just execute it. Otherwise invoke tclsh to run it.

Another problem could be that you redefined the PATH variable. On linux, the PATH variable normally contains a list of directories where executable commands can be found. To point to your sources, better use a different variable name, like SRCPATH or so. By redefining PATH, the tclsh command can not be found, unless it is in /work/source.

So the task1 rule of your Makefile could be reduced to:

task1: sourcefile1 sourcefile2
        tclsh evaltest.tcl
        # Or ./evaltest.tcl

This will execute evaltest.tcl if either sourcefile1 or sourcefile2 is newer than a file called task1. It is assumed that evaltest.tcl will create the task1 file. If either sourcefile doesn't exist and there is no rule to create it, make will tell you about that.