解引用指针并存储对指向数据的引用，然后获取引用地址并对其执行指针运算。 c++

Question

In order to make a diagram(of my own, to understand pointers/pointers-to-pointers/arrays) that is out of the scope this question, I want to know if it is adequate to assume the following:

int *intptr = new int[10]{0};
int &intref = *intptr;
int thirdInt = *((&intref)+2);//is this defined behavior and always equivalent to intptr[2]?????
delete [] intptr;

as the only comment in the code asks: does this code invoke undefined behavior or not work as expected by the comment?

Answer 1

then getting address of reference

To clarify this bit: It is not possible to "get address of a reference". When you apply addressof operator on a reference, you are getting the address of the referred object.

this code invoke undefined behavior

No.

always equivalent to intptr[2]?????

Yes (except in case of a class type with strange overload for operator &, but those are and should be hardly ever used).