Php/MySql 在 json 中查找/替换 utf-8 字符串

Question

I have this json string in a row in mysql database

{"editor":"<p>\u067e\u062f\u0631\u0627\u0645<\/p>"}

And want to find this and replace with <a> tag, but for test, I just select it but look like it can't find it, I used this query:

SELECT * FROM `wp_postmeta` WHERE `meta_value` LIKE '%\u067e\u062f\u0631\u0627\u0645%'

What is the problem?

This is original query:

$keyword_j = "\u067e\u062f\u0631\u0627\u0645";

$sql2 = "UPDATE `wp_postmeta` SET `meta_value` = REPLACE(meta_value, '".$keyword_j."', '<a href=\"\/".$link."\">".$keyword_j."<\/a>') WHERE `meta_value` LIKE '%".$keyword_j."%'";

Answer 1

You need to put escape sequence to achieve this. In Mysql, there is a second layer of escaping involved. So use this

SELECT * FROM `wp_postmeta` WHERE `meta_value` LIKE '%\\\\u067e\\\\u062f\\\\u0631\\\\u0627\\\\u0645%'

To automatically search and replace slash, use this

<?php
$keyword_j = "\u067e\u062f\u0631\u0627\u0645";
$x = str_replace("\\", "\\\\\\\\", $keyword_j);
echo $x;
?>

Update Query

$str = addslashes(htmlentities("<a href='".$link."'>".$keyword_j."</a>"));

$sql2 = "UPDATE wp_postmeta SET meta_value ='".$str."' WHERE meta_value LIKE '%".$x."%'";