如何在 javascript 中找到二维对象数组的索引

Question

So, what I'm trying to get is the index of a 2d array of objects, let's say I have the following

const arr = [
  [{id: 1}, {id:2}],
  [{id:3},{id:4},{id:5}]
  ]

If I'd want to get the index where id=3 it would be arr[1][0] , Is there any way to achieve this using vanilla JS or any helper library?

Answer 1

Might be a more efficient way to do it, but you could accomplish this via array.findIndex :

 const test = [ [{id: 1}, {id:2}], [{id:3},{id:4},{id:5}] ]; function find(arr, id) { const firstIndex = arr.findIndex(entry => entry.some(({id: x}) => x === id)); if (firstIndex > -1) { const secondIndex = arr[firstIndex].findIndex(({ id: x }) => x === id ); return [firstIndex, secondIndex]; } } console.log(find(test, 2)); // [0, 1] console.log(find(test, 4)); // [1, 1] console.log(find(test, 5)); // [1, 2]

Answer 2

 const arr = [ [{id: 1}, {id:2}], [{id:3},{id:4},{id:5}] ]; let searchIndex = 3; let x = arr.findIndex(sub => sub.find(el => el.id == searchIndex)); let y = arr[x].findIndex(el => el.id == searchIndex); console.log(x, y)

Answer 3

You can achieve this by nesting two for loops.

function findNestedIndices(array, id) {
  let i;
  let j;

  for (i = 0; i < array.length; ++i) {
    const nestedArray = array[i];
    for (j = 0; j < nestedArray.length; ++j) {
      const object = nestedArray[j];
      if (object.id === id) {
        return { i, j };
      }
    }
  }
  return {};
}

const array = [
  [{id: 1}, {id:2}],
  [{id:3},{id:4},{id:5}]
];

const { i, j } = findNestedIndices(array, 3);

console.log(i, j); // 1, 0

Answer 4

 const arr = [ [{id: 1}, {id:2}], [{id:3},{id:4},{id:5}] ]; function getIndex(arr, value){ let rowIndex = null; let valueIndex = null; arr.forEach(( nestedArray, index) => { if(;valueIndex) rowIndex = index. nestedArray,every((val. valIndex) => { if(val;id === value) { valueIndex = valIndex; return false } return true; }), }) return { rowIndex. valueIndex } } console,log(getIndex(arr, 3))