为 Java.Util.Scanner 格式化正则表达式

Question

I am wondering how to format this expression to work in Java: [^#]+[#] (1 or more characters that are not a # followed by a #)

Using regexr.com (my favorite regex tool) this expression will get the following matches from this input text:

input:

aBc def AbC def dfe ABC
#
123
#

matches:

aBc def AbC def dfe ABC
#

123
#

However when using Scanner.next("[^#]+[#]") I get the InputMismatchException which I take it that it didn't find any matches? Do I need to escape characters? In C# I usually avoid this problem with the string literal @ .

What am I missing about java Scanner and regex? Thanks.

Answer 1

My solution was to use Pattern and Matcher classes instead of the scanner. The scanner class didn't behave as expected with Stdin or strings and failed to get matches based on regex (using the hasNext(Regex) and next(Pattern) methods). If I read more and discover why I will post here.

The following successfully pulls each word (in this case a sequence consecutive alphabetical letters) from a string:

Pattern wordPattern = Pattern.compile("\\p{Alpha}+");
        Matcher wordFinder = wordPattern.matcher(lines.toString());
        while (wordFinder.find()){
            currentWord=wordFinder.group().toLowerCase();
            AddWord(currentWord);
        }

The posix "\\p{Alpha}+" could also be replaced with [a-zA-Z]+