Typescript - 在 function 上需要无参数的通用类型

Question

Is it possible to require a generic type on a function without parameters?

Example:

function myFunc<T>() {
  return {} as T
}

const a = myFunc() // a: unknown

I want to make the generic type required, but couldn't find anything about it.

Answer 1

function myFunc<T>() {
  return {} as T
}

const a = myFunc<SomeObject>() // a:SomeObject

seems to work just fine.