如何使用调用 shell 脚本的目录？

Question

I am trying to make a script to automate the creation of files and input of certain data in the files, sort of like a template. For example, if the script is called cpp (Just an example, not the actual script name), when I run cpp <filename> it should create a file in the current directory without me having to tell it what the directory is. Right now, I have to hard code a root directory into the script. The basic functionality of the script is something like this (I have validations and stuff, but this is the main function):

touch "$FILE_PATH" (this is the part that I have to hard code)
echo -e "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n\t\n}" > "$FILEPATH"
nvim "$FILE_PATH"

In this situation, I have to declare the file path to be FILE_PATH="$HOME/<a specific directory>/$1.cpp" , meaning when I call on the script, I have to pass an argument relative to the hard-coded location, like perhaps cpp automation/file_manager/shell/apartment . Is there a way for a shell script to automatically find the directory it is called on, so it can be more dynamic and flexible (Go to the directory automation/file_manager/shell/apartment and call cpp apartment to get the same result)? Kind of like vim or neovim, where it creates a file in the current directory.

Answer 1

You can use

    `dirname $0`

in your bash script. This would take the value of the directory where your script is placed. You would be able to execute your bash from anywhere as long as you have the right access.

Good practice:

 #initiate the dir name dir=`dirname $0` #initiate the name of your file file="my_filename" #use as needed: # create file in current bash directory touch $dir/$file # append echo -e "my_cpp_script" >> $dir/$file #call cpp $dir/$file