如何在第三个数组中对两个 arrays 的值进行分组？

Question

I have bellow this two arrays:

var t1 = ["18:00", "19:00", "20:00"]
var t2 = ["44:00", "23:00", "21:00"]

and I want to group their values in another array like this

var t3 = ["18:00 - 44:00", "19:00 - 23:00", "20:00 - 21:00"]

I tried some things with nested for loops and maps but I didn't even get close to what I expected.

Answer 1

You could do it like this:

 var t1 = ["18:00", "19:00", "20:00"] var t2 = ["44:00", "23:00", "21:00"] var t3 = t1.map((_, i) => `${t1[i]} - ${t2[i]}`); console.log(t3);

Answer 2

var t1 = ["18:00", "19:00", "20:00"] var t2 = ["44:00", "23:00", "21:00"] var t3 = [] for(var i = 0; i < t1.length; i++){ t3.push(`${t1[i]} - ${t2[i]}`); }

Answer 3

var t3 = t1.map((t, index) => `${t} - ${t2[index]}`);

Answer 4

 var t1 = ["18:00", "19:00", "20:00"]; var t2 = ["44:00", "23:00", "21:00"]; let t3 = []; for (let i=0; i<t1.length; i++) { t3.push(t1[i]+" - "+t2[i]); } console.log(t3);

Answer 5

You can map through the first array and adding the value of the second array , by using the index value:

var t1 = ["18:00", "19:00", "20:00"]
var t2 = ["44:00", "23:00", "21:00"]

var t3 = t1.map((element, index) => {
  return element + ' - ' + t2[index]
})

The map method offers access to the index