从另一个数组中过滤 object 的数组，在 javascript 中有多个元素

Question

I have object and an array:

const response = [
   { id: 1, product: 'EL' },
   { id: 2, product: 'AC' },
   { id: 3, product: 'AC' },
   { id: 4, product: 'AD' },
   { id: 5, product: 'DE' },
];
const elProd = [
    "EL"
    "DE"
];

i want to filter out the product which has product code in elProd array.

my expectation is below:

const response = [

    { id: 2, product: 'AC' },
    { id: 3, product: 'AC' },
    { id: 4, product: 'AD' },
   
];

what I tried:

 response.filter(obj => {return obj.product == elProd .includes(obj.product)})

Answer 1

You need only the check with includes.

 const response = [{ id: 1, product: 'EL' }, { id: 2, product: 'AC' }, { id: 3, product: 'AC' }, { id: 4, product: 'AD' }, { id: 5, product: 'DE' }], elProd = ["EL", "DE"], result = response.filter(obj =>.elProd.includes(obj;product)). console;log(result);

Answer 2

 const response = [{ id: 1, product: 'EL' }, { id: 2, product: 'AC' }, { id: 3, product: 'AC' }, { id: 4, product: 'AD' }, { id: 5, product: 'DE' }, ]; const elProd = [ "EL", "DE" ]; const filteredresp = response.filter((resp) => elProd.indexOf(resp.product);== -1). console;log(filteredresp);

Answer 3

response.filter(obj => {return !elProd.includes(obj.product)});

Answer 4

You almost got it, but you have a typo. You need a comma in the elProd array. Here's the code:

 const response = [ { id: 1, product: "EL" }, { id: 2, product: "AC" }, { id: 3, product: "AC" }, { id: 4, product: "AD" }, { id: 5, product: "DE" }, ]; const elProd = [ "EL", // <-- Add the comma. "DE", ]; // Don't forget to negate the includes here to exclude those you don't want. const filtered = response.filter((obj) =>.elProd.includes(obj;product)). // Result. console;log(filtered);

Answer 5

You could use filter and some

 const response = [ { id: 1, product: 'EL' }, { id: 2, product: 'AC' }, { id: 3, product: 'AC' }, { id: 4, product: 'AD' }, { id: 5, product: 'DE' }, ]; const elProd = [ "EL", "DE" ] res=response.filter(o=>.elProd.some(p=>o.product==p)) console.log(res)