[英]Convert decimal to date format SQL
I am trying to convert a column FC_FROM_DATE containing decimal values (ex. 20,200,721) into a date format 2020/07/21.我正在尝试将包含十进制值(例如 20,200,721)的列 FC_FROM_DATE 转换为日期格式 2020/07/21。
I have tried this code我试过这段代码
SELECT TO_DATE(CHAR(CAST(FC_FROM_DATE AS DECIMAL(8,0))), 'YYYY/MM/DD')
FROM MARKETS.FORECAST
I get an error我收到一个错误
Argument for chr should be between 0 and 127
chr 的参数应该在 0 到 127 之间
Would much appreciate your help!非常感谢您的帮助!
If you are using Oracle then you can use the following query:如果您使用的是 Oracle 那么您可以使用以下查询:
SELECT TO_DATE(CAST(FC_FROM_DATE AS VARCHAR(8), 'YYYY/MM/DD') FROM Table
Seeing as the persisted format is YYYYMMDD
you could convert the value to a varchar(8)
and then use CONVERT
to get a Date
instance.看到持久格式是
YYYYMMDD
,您可以将值转换为varchar(8)
,然后使用CONVERT
获取Date
实例。
SELECT CONVERT(DATE, CAST(FC_FROM_DATE AS VARCHAR(8))) FROM MARKETS.FORECAST
Ideally Dates are stored as Date and a Date with a time component is stored as DATETIME2 (or equivalent if not Sql Server).理想情况下,日期存储为日期,带有时间组件的日期存储为 DATETIME2(如果不是 Sql 服务器,则等效)。
DECLARE @FC_FROM_DATE decimal(8,0) = 20200721
SELECT CONVERT(DATE, CAST(@FC_FROM_DATE AS VARCHAR(8)))
2020-07-21
2020-07-21
Disclaimer: This works in MS Sql Server.免责声明:这适用于 MS Sql 服务器。
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