如何使用 Slim 框架上传图片

Question

I want to storage a image in server and save the path in MySQL, but i'm not finding a good code to do it.

I found this, but does not work:

$container = $app->getContainer();
$container['upload_directory'] = __DIR__ . '../uploads';


$app->post('/photo', function (Request $request, Response  $response) use ($app) {

$directory = $this->get('upload_directory');

$uploadedFiles = $request->getUploadedFiles();

$uploadedFile = $uploadedFiles['picture'];
  if($uploadedFile->getError() === UPLOAD_ERR_OK) {
    $filename = moveUploadedFile($directory, $uploadedFile);
    $response->write('uploaded ' . $filename . '<br/>');
 }

 });

function moveUploadedFile($directory, UploadedFile $uploadedFile){
             $extension = pathinfo($uploadedFile->getClientFilename(), 
             PATHINFO_EXTENSION);
             $basename = bin2hex(random_bytes(8));
             $filename = sprintf('%s.%0.8s', $basename, $extension);
             $uploadedFile->moveTo($directory . DIRECTORY_SEPARATOR . $filename);

            return $filename;
            
        }

Somebody knows how to upload image and save the path in MySQL?

Answer 1

First you need a database connection for MySQL. Read more

Then create a table, eg files(id, path, filename)

To insert the record (after the upload) into the table, you could use an SQL statement as follows:

// ...
$filename = moveUploadedFile($directory, $uploadedFile);
$response->getBody()->write('File uploaded: ' . $filename);

$row = [
    'path' => $directory,
    'filename' => $filename
];
$sql = "INSERT INTO files SET path=:path, filename=:filename;";
$pdo->prepare($sql)->execute($row);

// ...

return $response;

Please note that $response->write('...') will not work. It must be $response->getBody()->write('my content'); .

Edit: Make sure that the uploads/ directory exists and the directory has write access. For example chmod -R 1777 uploads/