为什么此代码会给出错误“无法将 'char*&' 类型的非 const 左值引用绑定到 'char*' 类型的右值”

Question

Why does the following code give this error:

cannot bind non-const lvalue reference of type 'char &' to an rvalue of type 'char '

#include <string>

int main()
{
    std::string p {"Test string"};
    auto &r = p.data();
    return 0;
}

The type of the pointer returned by std::string::data is char * . And the type of variable r is char *& . So why, in this case, the type of char * cannot be referenced by a type of char * ?

Answer 1

The reason is that the C++ standard doesn't allow non-const references to bind to temporaries, and std::string::data returns a pointer by value. Only const reference can do that, and prolong the life of the temporary object.

In your case you either need to make your reference const.

const auto& r = p.data();

Or better, just create a variable that will store the pointer for you, as pointers are cheap to copy around.

const char* r = p.data();