我想在单独的行上打印每个数字的平方

Question

def square_non (n):
    for x in range(0,21):
         if x < n:
             return (x*x)
         else:
            return "Please try again!"

Tried to debug but I don't comprehend why the for-loop isn't continuing.

Update: Just used list-comprehension and generators, which made the whole thing easy

Answer 1

If you want to print the values, you should not return them but print them.

def square_non (n):
    for x in range(0,21):
         if x < n:
             print(x*x)
         else:
             print("Please try again!")

If you return x*x , this function will terminate at the moment it reaches this return statement, which is in the first run of the loop. So, the function just returns 0, no matter what you pass as an argument.

Answer 2

Return will end the execution of loop and will return control to calling function. So best way is to get all values in array and return it.

Try this code:

def square_non (n):
    squares = [] 
    for x in range(0,21):
         if x < n:
             squares.append(x*x)
         else:
             return squares

def calling_function():   #Function from which it get called
    squares = square_non(10) #Assume 10 for example 
    for square in squares:
        print(str(square) + '\n')

Answer 3

If you want to print the value in seperate line then simple use print(square_non(n),'\n') and add '\n' which will create new line.

Here is the code

def square_non (n):
    for x in range(0,21):
         if x < n:
             return (x*x)
         else:
            return "Please try again!"
print(square_non(n),'\n')

Answer 4

As they mentioned in the comments already the issue here is the return because a loop as soon as hits a return it will terminate it.

The most simple fix for your code would be this --->:

def square_non(n):

for x in range(0, 21):
    
    if x < n:
        print(x*x)
    else:
        print("Please try again!")
        return

        
x = square_non(5)

As you can see I do use return after the 'else' statement exactly for the reason why your code was wrong, to terminate the code.

As also was mentioned by a comment earlier, you can append the result into a list:

def square_non(n):

squared_list = []

for x in range(0, 21):
    
    if x < n:
        x = (x * x)
        squared_list.append(x)
    else:
        print("Please try again!")
        break
return squared_list
    

        
x = square_non(10)
print(x)

So the list is stored now in X, and you can use it. I mentioned this because it's a great way to understand what return does:

1. Terminate the execution of a Loop
2. Return a value, data..basically something that then you can store it in a variable (if you don't do this, the function would return None)