如何在某些字符后从字符串的开头和结尾删除？

Question

I have this: /opt/lampp/htdocs/website/inn/hemlata993/93/

I want to remove /opt/lampp/htdocs and the / at the end so eveyrthing after the 2nd / at the end should get removed. In the above example /93 should get removed hence it would be:

/website/inn/hemlata993/

I tried doing this:

$files = glob($dirName."*.*");
for ($i = 0; $i < count($files); $i++) {
    $image = $files[$i];
    echo $image;
    $arr = explode('/opt/lampp/htdocs', $image);
    $important = $arr[1];
 
    echo '<img src="'.$important.'" width="100" height="100" alt="Random image" />' . "<br /><br />";

}

This removes /opt/lampp/htdocs I was wondering how do I remove the end one as well, and store it in one variable? I try using substr, but after removing the first part its storing in array I assume so I am not able to do that. How can I get /website/inn/hemlata993/ ?

Answer 1

One way to achieve this would be to use a regex to match everything after /opt/lampp/htdocs and up to and including the 2nd to last / . For example:

$image = '/opt/lampp/htdocs/website/inn/hemlata993/93/';
$image = preg_replace('#/opt/lampp/htdocs(/.*/)[^/]+/[^/]*$#', '$1', $image);
echo $image;

Output:

/website/inn/hemlata993/

Demo on 3v4l.org

Answer 2

I'd go for a solution that doesn't depend on your website's physical location:

$path = '/opt/lampp/htdocs/website/inn/hemlata993/93/';
if (preg_match('#/website/(.*)/(?=\d+/)#', $path, $matches)) {
  $path = $matches[0];
}

This, however, assumes that:

• /website is where the files are located within the server's document root,
• the paths always end with one or more digits at the end (before the last / ).

Demo