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C++:实现 ln(a) 的数值逼近

[英]C++: Implementing a numeric approximation for ln(a)

I want to implement the formula:我想实现公式:

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#include <iostream>
#include <cmath>
#include <limits>

using namespace std;

int main(){
    double a, eps = numeric_limits<double>::epsilon();
    cout << "a=";
    cin >> a;
    double w = sqrt(a), prod = 1 + w;
    int n = 1;
    do {
        w = sqrt(w);
        prod *= 1 + w;
        cout << "ln(" << a << ")=" << ldexp(a-1, n)/prod << endl;
        n++;
    } while(abs(w - 1) > eps);

    return 0;
}

But eg ln(2.78787)=0.512639 and that cannot be true.但例如 ln(2.78787)=0.512639 这不可能是真的。 Where is the mistake?错误在哪里?

Initial conditions for the loop are off.循环的初始条件为关闭。 Start with从...开始

double w = a, prod = 1;

and the program would produce expected results该计划将产生预期的结果

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