简体   繁体   English

将图 object 传递给 plotly 破折号中的图形

[英]Passing Figure object to Graph in plotly dash

When I try to pass a Figure object to the dcc.Graph() in my layout, I get en error that says:当我尝试将Figure object 传递到布局中的dcc.Graph()时,我收到错误消息:

dash.exceptions.InvalidCallbackReturnValue: The callback ..graph.figure.. is a multi-output.
    Expected the output type to be a list or tuple but got: 
    Figure({# the content of the figure})

my code is like:我的代码是这样的:

import dash
import dash_core_components as dcc
import dash_html_components as html
from dash.dependencies import Input, Output
import plotly.express as px

app.layout = html.Div([
    dcc.Graph(
        id='graph'
    )
])

@app.callback(
    [
        Output('graph', 'figure'),
    ],
    [
        Input('my-input', 'value')
    ]
)
def gen_graph(value):
    dff = # my filtered df
    fig = px.line(dff, x='x_var', y='y_var')
    return fig

Feels like I'm missing something in how the Figure should be passed to the dcc.Graph() .感觉我在如何将Figure传递给dcc.Graph()遗漏了一些东西。 Any ideas?有任何想法吗?

You structured your Output as a list, that makes it a multi-output callback.您将Output为一个列表,这使其成为一个多输出回调。 Just change it like this:像这样改变它:

@app.callback(
    Output('graph', 'figure'),
    [
        Input('my-input', 'value')
    ]
)
def gen_graph(value):
    ...

Alternatively, you could wrap your output in brackets to make it a list ( return [fig] ).或者,您可以将 output 括在括号中以使其成为一个列表( return [fig] )。 Either way should work fine.无论哪种方式都应该工作正常。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM