[英]Calculating distance of latitude/longitude on pandas dataframe using GeoPy
I'm trying to calculate distance between latitude and longitude using geopy on a Pandas Dataframe.我正在尝试使用 Pandas Dataframe 上的 geopy 计算纬度和经度之间的距离。
here is my dataframe:这是我的 dataframe:
latitude longitude altitude
-15.836310 -48.020298 1137.199951
-15.836360 -48.020512 1136.400024
-15.836415 -48.020582 1136.400024
-15.836439 -48.020610 1136.400024
-15.836488 -48.020628 1136.599976
I tried two different ways:我尝试了两种不同的方法:
from geopy import distance
for i in range(1, len(df)):
before = (df.loc[i-1, 'latitude'], df.loc[i-1, 'longitude'])
actual = (df.loc[i, 'latitude'], df.loc[i, 'longitude'])
df.loc[i, 'geodesic'] = distance.distance(before, actual).miles
error:错误:
KeyError: 0
Apparently, df.loc[i, 'column_name']
does not work.显然, df.loc[i, 'column_name']
不起作用。
and:和:
from geopy import distance
df['geodesic'] = distance.distance((df.latitude.shift(1), df.longitude.shift(1)), (df.latitude, df.longitude)).miles
Error:错误:
ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
Official GeoPy Documentation:官方 GeoPy 文档:
from geopy import distance
newport_ri = (41.49008, -71.312796)
cleveland_oh = (41.499498, -81.695391)
print(distance.distance(newport_ri, cleveland_oh).miles)
I got the error.我得到了错误。
1 - I had to check if latitude
or longitude
is NaN
. 1 - 我必须检查latitude
或longitude
是否为NaN
。
2 - I couldn't set time
as index. 2 - 我无法将time
设置为索引。 (i don't know why, that's took a long time to discover) (我不知道为什么,这花了很长时间才发现)
Once checked this, the error was gone.一旦检查了这一点,错误就消失了。
raw = """latitude;longitude;altitude
-15.836310;-48.020298;1137.199951
-15.836360;-48.020512;1136.400024
-15.836415;-48.020582;1136.400024
-15.836439;-48.020610;1136.400024
-15.836488;-48.020628;1136.599976"""
import pandas as pd
from io import StringIO
from geopy import distance
data = StringIO(raw)
df = pd.read_csv(data, sep=";")
df1 = df.drop(['altitude'], axis=1)
locations = df1.apply(tuple, axis=1)
for counter in range(len(locations) - 1):
print(distance.distance(locations[counter], locations[counter + 1]).miles)
from df = pd.read_csv(data, sep=";")
it's the same as you have your code, i made it testable.从df = pd.read_csv(data, sep=";")
它与您的代码相同,我使其可测试。
After that, df1 = df.drop(['altitude'], axis=1)
drop the table z axis, not needed in this application.之后, df1 = df.drop(['altitude'], axis=1)
删除表格 z 轴,在此应用程序中不需要。
convert the df1 to tuples, and loop through locations and you got your distance将 df1 转换为元组,并循环遍历位置,你就得到了你的距离
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