[英]Mongoose query returning more than one result
My database structure is looking like this:我的数据库结构如下所示:
{
'name' : 'entry one'
'project' :
[
{companyName : 'a name', contactPerson : [{ work_email: 'test@test.com'}] } ,
{companyName : 'a name1', contactPerson : [{ work_email: 'test1@test.com'}] } ,
{companyName : 'a name2', contactPerson : [{ work_email: 'test2@test.com'}] }
]
}
{
'name' : 'entry 2'
'project' :
[
{companyName : 'another name', contactPerson : [{ work_email: 'testing@test.com'}] } ,
{companyName : 'another name1', contactPerson : [{ work_email: 'testing1@test.com'}] } ,
{companyName : 'another name 2', contactPerson : [{ work_email: 'testing2@test.com'}] }
]
}
What i want is to find the companyName that belongs to a given work_email.我想要的是找到属于给定工作电子邮件的公司名称。 So if the work_email is test@test.com
the company name that should be returned should be 'a name'
因此,如果 work_email 是test@test.com
,则应返回的公司名称应为'a name'
So the query i built with mongoose is this:所以我用 mongoose 构建的查询是这样的:
const projects = await ClientManagers.findOne({'project.contactPerson.work_email' : 'test@test.nl'} , 'project.companyName');
But this is returning all company names (from entry one) not the single one i am looking for.但这将返回所有公司名称(从条目一开始),而不是我正在寻找的单一名称。
Filtering will always return whole document.过滤将始终返回整个文档。 You need to use projection to "reshape" it.您需要使用投影来“重塑”它。 You can consider the $ (projection) operator :您可以考虑$(投影)运算符:
const projects = await ClientManagers.findOne({'project.contactPerson.work_email' : 'test@test.nl'} , { 'project.$': 1 });
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