从 python 的不同列表中选择最大值

Question

I have a list that looks like this, which I was able to get after scraping a website, but in this case these are different dimension of images from the website:

[72, 72]
[95, 96]
[13, 60]
[227, 973]

I have tried this but it is not giving me what I want:

    for items in height, width:
        dimension.append(items)
    print(max(dimension))

I want to be able to select the one with the maximum value which is:

[227, 973]

Answer 1

I assume you have a two-dimensional list and are interested in finding the sublist, which contains the maximal element.

To find this, you can simply use pythons build in max function and provide a comparison function via the key parameter. The key parameter takes a function of which the result is used for comparison, so for example: key=lambda sublist: max(sublist) . In this case, you can even simply pass the max() function itself as key

To sum it up, something like this should work for you:

x = [[72, 72], [95, 96], [13, 60], [227, 973]]
 
max_pair = max(x, key=max)
print(max_pair)

After the discussion with you , I assume you get the dimension values in a for loop (and don't have them in a list at the beginning) and want to get the max at the end. I modified your code a bit and hope this works for you. It still uses the same idea as mentioned before:

dimensions = []
for something in something_else:
    image = get_image()
    height, width, _ = image.shape
    dimensions.append([height, width])
max_dimension = max(dimensions, key=max)
print(max_dimension)