如何将dict项目转换为句子

Question

I have a input data with two dict index and notes.

indexes={'Laptops':'1','Mob':'2','Cars':'3','Bus':4}
    Notes={
 

   
    'indexs':[1,3],
    'Laptops':[
        "dell","asus","acer"
    ],
    'Mob':[
        "mi","realme"
    ],
   'Bus':[
     "aB"
 
   ],
    'Cars':["Not found"
         ]

}

Created a sentence generator

def SenGen(alpha,beta):
    for a,b in alpha.items():
        for c,d in beta.items():
            if c in a:
                print(f"{a} are ", end="")
                for i, e in enumerate(b):
                    if i == len(b)-1:
                        print(f"and {e}. ", end="")
                    elif i == len(d)-2:
                        print(f"{e} ", end="")
                    else:
                        print(f"{e}, ", end="") 

with the help of SenGen, i generated a sentence which is shown below.

SenGen(Notes,indexes)

output

Laptops are dell, asus, and acer. Mob are mi, and realme. Bus are and aB. Cars are and not found. 

in the above output in laptops i have 3 words which is seprated by 'and' ,**In mob i have two words which is separated by 'and' **.While in the Bus i have only one word. but 'and' is front of aB , and in thecase of its same cars i have not found .

my desired output should be like shown below.

output:

Laptops are dell, asus, and acer. Mob are mi, and realme. Bus are aB. Cars are  not found. 

i followed set of cases to fix that issue shown below.

1.if i == len(b)==1:
                            
    print(f" is {e} ", end="")

2.if i == len(b)==0:
                            
    print(f" is {e} ", end="")
3.if i == len(b)<1:
                            
    print(f" is {e} ", end="")
4.if i == len(b)>1:
                            
    print(f" is {e} ", end="")

but im unable to solve it.

Answer 1

You could solve your problem by relying on lists and its methods in Python:

keys = list(Notes.keys())
keys.remove('indexs')

for key in keys:
    first_clause = ', '.join(Notes[key][:-1])
    last_clause = Notes[key][-1:][0]
    
    if len(first_clause) == 0:
        print(key + ' is ', last_clause, end='. ')
    else:
        print(key + ' are ', first_clause, ', and ', last_clause, end='. ')

Then your output is:

Laptops are  dell, asus , and  acer. Mob are  mi , and  realme. Bus is  aB. Cars is  Not found. 

Answer 2

Validate before.

def SenGen(alpha,beta):
    for a,b in alpha.items():
        for c,d in beta.items():
            if c in a:
                print(f"{a} are ", end="")
                if len(b) == 1:
                    print(f"{e}. ", end="")
                else:
                    for i, e in enumerate(b):
                        if i == len(b)-1:
                            print(f"and {e}. ", end="")
                        elif i == len(d)-2:
                            print(f"{e} ", end="")
                        else:
                            print(f"{e}, ", end="")